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Mathematics 25 Online
OpenStudy (anonymous):

find the value of the sine for angle A.

OpenStudy (anonymous):

OpenStudy (anonymous):

@Directrix

OpenStudy (campbell_st):

find the value of a using pythagoras \[a^2 =12^2 - 8^2\] then sin(A) = opposite side/hypotenusse hope it helps

OpenStudy (anonymous):

so 80?

Directrix (directrix):

The sine of an acute angle of a triangle is equal to the ratio of the leg opposite that angle to the hypotenuse. First up, you have to find the length of side a. 12^2 = 8^2 + a^2 @cutegirl --> Solve that for a. Then, there's more work to do.

OpenStudy (anonymous):

144=a^2+64

Directrix (directrix):

Subtract 64 from both sides of that.

OpenStudy (anonymous):

80=a^2

Directrix (directrix):

Take the square root of 80. Don't mess with approximations because the answer options are in exact form.

OpenStudy (anonymous):

=4√5

OpenStudy (anonymous):

4 sqaured 5

Directrix (directrix):

Sin(A) = 4√5 / 12 How does that simplify?

Directrix (directrix):

4 goes into 12 how many times/

OpenStudy (anonymous):

3

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

So, Sin(A) = 4√5 / 12 = √5 /3

OpenStudy (anonymous):

thanks so much

Directrix (directrix):

You are welcome.

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