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find the value of the sine for angle A.
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@Directrix
find the value of a using pythagoras \[a^2 =12^2 - 8^2\] then sin(A) = opposite side/hypotenusse hope it helps
so 80?
The sine of an acute angle of a triangle is equal to the ratio of the leg opposite that angle to the hypotenuse. First up, you have to find the length of side a. 12^2 = 8^2 + a^2 @cutegirl --> Solve that for a. Then, there's more work to do.
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144=a^2+64
Subtract 64 from both sides of that.
80=a^2
Take the square root of 80. Don't mess with approximations because the answer options are in exact form.
=4√5
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4 sqaured 5
Sin(A) = 4√5 / 12 How does that simplify?
4 goes into 12 how many times/
3
@Directrix
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So, Sin(A) = 4√5 / 12 = √5 /3
thanks so much
You are welcome.
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