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An arrow is shot vertically upward from a platform 43 ft high at a rate of 171 ft per sec. When will the arrow hit the ground? Use the formula: h=-16t^2+vt+h
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can you set height (h) to 0 and plug in 171ft/s into v and then solve for t?
since arrow will have height of 0 when it hits the ground
If h is the height of an object above ground, at time t, then the object hits the ground when h = 0.
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