What is the equation of the graphed line?
http://static.k12.com/calms_media/media/1503000_1503500/1503205/3/0539777c91888fdb4df047b53ea5acb32adf5549/MS_IMC-140516-1000015.jpg
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OpenStudy (itsbribro):
are these the points? (0,0) (5, -1)
OpenStudy (anonymous):
yes
OpenStudy (catlover5925):
ur slope is -5/1
but do you want the equation in slope intercept form??
OpenStudy (anonymous):
use these points to fine the slope
OpenStudy (itsbribro):
|dw:1418408408129:dw|
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OpenStudy (itsbribro):
so would the blank be -5?
OpenStudy (anonymous):
yes
after that use this equation
y-yo=m(x-x)
OpenStudy (anonymous):
pick one of these points
OpenStudy (anonymous):
for yo and xo
OpenStudy (catlover5925):
@AJ01 the slope is -5/1 right??
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OpenStudy (anonymous):
the slope should (y-yo)/(x-xo)=-1/5
OpenStudy (itsbribro):
then i would find the answer to -1/5 right?
OpenStudy (anonymous):
yes
OpenStudy (itsbribro):
which would be -0.2
OpenStudy (anonymous):
yeah
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OpenStudy (itsbribro):
okay
OpenStudy (anonymous):
use this equation y-yo=m(x-xo)
where m is the slope and pick one point for xo and yo
OpenStudy (itsbribro):
okay
OpenStudy (itsbribro):
to bad i cant give both of you a medal :/ thank you both for your help :)