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Mathematics 8 Online
OpenStudy (itsbribro):

What is the equation of the graphed line? http://static.k12.com/calms_media/media/1503000_1503500/1503205/3/0539777c91888fdb4df047b53ea5acb32adf5549/MS_IMC-140516-1000015.jpg

OpenStudy (itsbribro):

are these the points? (0,0) (5, -1)

OpenStudy (anonymous):

yes

OpenStudy (catlover5925):

ur slope is -5/1 but do you want the equation in slope intercept form??

OpenStudy (anonymous):

use these points to fine the slope

OpenStudy (itsbribro):

|dw:1418408408129:dw|

OpenStudy (itsbribro):

so would the blank be -5?

OpenStudy (anonymous):

yes after that use this equation y-yo=m(x-x)

OpenStudy (anonymous):

pick one of these points

OpenStudy (anonymous):

for yo and xo

OpenStudy (catlover5925):

@AJ01 the slope is -5/1 right??

OpenStudy (anonymous):

the slope should (y-yo)/(x-xo)=-1/5

OpenStudy (itsbribro):

then i would find the answer to -1/5 right?

OpenStudy (anonymous):

yes

OpenStudy (itsbribro):

which would be -0.2

OpenStudy (anonymous):

yeah

OpenStudy (itsbribro):

okay

OpenStudy (anonymous):

use this equation y-yo=m(x-xo) where m is the slope and pick one point for xo and yo

OpenStudy (itsbribro):

okay

OpenStudy (itsbribro):

to bad i cant give both of you a medal :/ thank you both for your help :)

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