Question

*******will give medals and fan*******
Three times the greatest of the three consecutive even integers exceeds twice the least by 38. What are the integers. Type your response in the space provided.

Answer 1

so you need to write this as an equation first. any ideas?

Answer 2

i have no idea its like a a forenlanguge

Answer 3

lol :) so 3 consecutive integers can be written as "n, (n + 1), and (n + 2)." but since these are consecutive \(\underline{even}\) integers, they can be written as "n, (n + 2), and (n + 4)"

the problem says "Three times the greatest of the three consecutive even integers" which can be written algebraically as 3(n + 4). since (n + 4) is the greatest of the three numbers

"exceeds twice the least by 38" which can be written out as 2n + 38. since n is the least number. and + 38 since it says "exceeds"

so our equation is 3(n + 4) = 2n + 38

Answer 4

now you can solve for n, and then solve for (n + 2) and (n + 4)

Answer 5

can you work that out to solve for n?

Answer 6

@priecetheveil you there?

Answer 7

sorry i got caught up in something

Answer 8

that's fine :) can you do that though?