You can place weights on both sides of the weighing balance and you need to measure all weights between 1 and 1000. For example if you have weights 1 and 3, now you can measure 1,3 and 4 like the earlier case, and also you can measure 2, by placing 3 on the side and 1 on the side which contains the substance to be weighed. So the question is how many minimum weights and of what denominations you need to measure all weights from 1kg to 1000kg

Will Medal!! Please help.

Question

You can place weights on both sides of the weighing balance and you need to measure all weights between 1 and 1000. For example if you have weights 1 and 3, now you can measure 1,3 and 4 like the earlier case, and also you can measure 2, by placing 3 on the side and 1 on the side which contains the substance to be weighed. So the question is how many minimum weights and of what denominations you need to measure all weights from 1kg to 1000kg 

Will Medal!! Please help.

anonymous · Answer

Its logic is 3^n. Chose n nearest to the highest weight needed.

zbrandz23 · Answer

ok, I somewhat get it. Can you elaborate a little more?

anonymous · Answer

Eg to get 40 kgs I use weights : 27+9+3+1

no of weights used is 4 as  40 lies between 27(3^3) and 81(3^4). Hence your weights will be decided by power of 3.
There are wonderful programs written in python , you can consult stackoverflow.com for details if you are interested

zbrandz23 · Answer

Thanks for helping me with this problem gotta take a break ill be back in 15

anonymous · Answer

great