Using your function f(x) from question 2, demonstrate and explain how to find the average rate of change between year 3 and 5, and between year 5 and 7. Explain what the average rate of change represents to the frog population.
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OpenStudy (anonymous):
my function is f(x) = a times b^x
OpenStudy (anonymous):
@ranga
OpenStudy (anonymous):
@wmj259
OpenStudy (wmj259):
what was the question 2 function?
OpenStudy (anonymous):
f(x) = a * (b)^x
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OpenStudy (anonymous):
are you there? @wmj259
OpenStudy (calculusfunctions):
The average rate of change (slope of a secant) of a function f(x) over the interval\[x _{1} \le x \le x _{2}\]is\[\frac{ f(x _{2})-f(x _{1}) }{ x _{2}-x _{1} }\]
OpenStudy (anonymous):
thank you!!! but what is x2 and x1????
OpenStudy (anonymous):
@calculusfunctions ^^
OpenStudy (calculusfunctions):
x sub 1 is the smaller of the two x values and x sub 2 is the larger.
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OpenStudy (calculusfunctions):
Hence if you have to find the average rate between year 3 and year 5, then x sub 1 is 3 and x sub 2 is 5. Understand @haha.lena ?
OpenStudy (anonymous):
yes! thank you so much! you are officially medalled. lol xD