Solve, using the substitution method.
y – 3x = 7
21 + 9x = 3y
A.
There is no solution.
B.
There are an infinite number of solutions.
C.
The solution is (1, 10)
D.
The solution is (28, 0)
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OpenStudy (danjs):
solve the first equation for y
y = 3x + 7
OpenStudy (danjs):
place that y into the second equation
OpenStudy (danjs):
21 + 9x = 3*(3x + 7)
OpenStudy (twizttiez):
I think B
OpenStudy (danjs):
i didnt solve it , idk
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OpenStudy (anonymous):
So, from where he left off, distribute the 3out
OpenStudy (anonymous):
You'll get 21+9x=9x+21
OpenStudy (twizttiez):
y – 3x = 7
y – 3x+3x = 7+3x
y + 0x = 3x + 7
y + 0 = 3x + 7
y = 3x + 7
Therefore infinite number of solutions
OpenStudy (anonymous):
That's the exact same line isn't it?
OpenStudy (anonymous):
Good job. It's the exact same line, therefore there are an infinite number.
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OpenStudy (twizttiez):
YAY!
OpenStudy (danjs):
It would be infinite solutions because the second equations is a constant scalar multiple of the first (-3)