Complete the equation for the linear function whose graph contains the point (5, −3) and has a slope of −1.25. y = x +
Please help me
@KlOwNlOvE
use the general form y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
Okay
so you plug in x = 5,y = -3 and m = -1.25 and simpify
Im sorry im bad at math Do i need to divide ??
Im stupid im sorry but i am
y - (-3) = -1.25(x - 5) i just replaced x ,y and m by -3,5 and -1.25
that gives y + 3 = -1.25x + 6.25 now subtract 3 from both sides of the '=' to get the equation in the form you require
No ones "stupid" just others have more practice in that field than others and thanks @cwrw238
right
i got 6.22
is that the correct answer??
can u please help me i have until 8:00
no subtract 3.00 from 6.25 so 6.25-3.00?
i got 3.25
yes now whats your new equation?
should be in y=mx+b form
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