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OpenStudy (anonymous):
Complete the equation for the linear function whose graph contains the point
(5, −3) and has a slope of −1.25.
y = x +
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OpenStudy (anonymous):
Please help me
OpenStudy (anonymous):
@KlOwNlOvE
OpenStudy (cwrw238):
use the general form
y-y1 = m(x-x1)
where m is the slope and (x1,y1) is a point on the line
OpenStudy (anonymous):
Okay
OpenStudy (cwrw238):
so you plug in x = 5,y = -3 and m = -1.25
and simpify
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OpenStudy (anonymous):
Im sorry im bad at math Do i need to divide ??
OpenStudy (anonymous):
Im stupid im sorry but i am
OpenStudy (cwrw238):
y - (-3) = -1.25(x - 5)
i just replaced x ,y and m by -3,5 and -1.25
OpenStudy (cwrw238):
that gives y + 3 = -1.25x + 6.25
now subtract 3 from both sides of the '=' to get the equation in the form you require
OpenStudy (anonymous):
No ones "stupid" just others have more practice in that field than others and thanks @cwrw238
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OpenStudy (cwrw238):
right
OpenStudy (anonymous):
i got 6.22
OpenStudy (anonymous):
is that the correct answer??
OpenStudy (anonymous):
can u please help me i have until 8:00
OpenStudy (anonymous):
no subtract 3.00 from 6.25 so
6.25-3.00?
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OpenStudy (anonymous):
i got 3.25
OpenStudy (anonymous):
yes now whats your new equation?
OpenStudy (anonymous):
should be in y=mx+b form
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