Mathematics
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OpenStudy (anonymous):
simplify : (3x)^2*x^-1
a)3x
b)9/x^2
c)9x
d)3/x^2
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OpenStudy (fibonaccichick666):
so any ideas on how to begin?
OpenStudy (anonymous):
3^2=9 i think it is C 9x
OpenStudy (fibonaccichick666):
3^2=9 is correct, how would you simplify the other parts though?
OpenStudy (fibonaccichick666):
what do you do to the exponents when you multiply like bases?
OpenStudy (anonymous):
subtract
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OpenStudy (anonymous):
add
OpenStudy (fibonaccichick666):
well yes in this case you would, but that is just adding a negative here
OpenStudy (anonymous):
so it would just b x *9x=9x
OpenStudy (fibonaccichick666):
well you have \(9x^2*x^{-1}\)
OpenStudy (fibonaccichick666):
what you typed that equaled 9x anctually equals \(9x^2\)
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OpenStudy (anonymous):
9/x^2
OpenStudy (fibonaccichick666):
how did you get that?
OpenStudy (anonymous):
9x^2*x^-1 2-1=1 9x*x=9x
OpenStudy (fibonaccichick666):
that would be correct, with correct reasoning.
OpenStudy (anonymous):
ok thank u
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OpenStudy (fibonaccichick666):
but you do not write 9*x*x, that is 9x^2, there is not inbetween step
OpenStudy (anonymous):
so b is the answer
OpenStudy (anonymous):
?
OpenStudy (fibonaccichick666):
yes, but you are writing 9x^2=9x above, you shouldn't do that. It only works for x=1 then
OpenStudy (anonymous):
or c
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OpenStudy (fibonaccichick666):
9x*x=9x^2
OpenStudy (fibonaccichick666):
it's 9x like you said
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
simplify: r^2s^4t/r^2st^3
a)s^3/t^2
b)s^3/t
c)s^2/t^3
d)s/t