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Given f(x)=2x^2+2x and g(x)=x+1, find the function (f/g)(x).
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divide
2x(x+1)/(x+1) = 2x
@bryn
Thanks, I understand that. How could I find the excluded value?
as denominator is x+1 => x can never be -1 cos at x=-1 the f/g becomes infinitty, so ans is x belongs to R-{-1}... always put denominator = 0 and find all x's forr which function becomes infinity...
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@bryn
So x=-1 would be the excluded value? @princeharryyy
yes
Thanks!!
wlcm!
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