A plumbing contracter charges $40 per hour plus a call-out fee of $25. if the contracter charged $165 for a job, how long did the job take?
say it took him \(t\) hours
that means he must have charged \(40\times t\) amount
and an additional $25 makes it : \[40\times t + 25\] yes ?
set that equal to 165 and solve \(t\)
\[40\times t + 25 = 165\]
So is the answer to this 165
Total Amount Charged = [Hourly Rate] x [#Hours] + [Call-out Fee]
Do you know the answer?
I didnt calculate it, you need to put the numbers.
idk where they go xD sorry im really dumb at maths
Total amount charged = 165 and call-out fee = 25 and hourly rate = 40
@ganeshie8 wrote the equation out for you above
whats the t
so you have, 40*t + 25 = 165 What would you do first to solve for the amount of time t ?
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