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OpenStudy (anonymous):
A plumbing contracter charges $40 per hour plus a call-out fee of $25. if the contracter charged $165 for a job, how long did the job take?
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ganeshie8 (ganeshie8):
say it took him \(t\) hours
ganeshie8 (ganeshie8):
that means he must have charged \(40\times t\) amount
ganeshie8 (ganeshie8):
and an additional $25 makes it :
\[40\times t + 25\]
yes ?
ganeshie8 (ganeshie8):
set that equal to 165 and solve \(t\)
ganeshie8 (ganeshie8):
\[40\times t + 25 = 165\]
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OpenStudy (anonymous):
So is the answer to this 165
OpenStudy (danjs):
Total Amount Charged = [Hourly Rate] x [#Hours] + [Call-out Fee]
OpenStudy (anonymous):
Do you know the answer?
OpenStudy (danjs):
I didnt calculate it, you need to put the numbers.
OpenStudy (anonymous):
idk where they go xD sorry im really dumb at maths
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OpenStudy (danjs):
Total amount charged = 165
and
call-out fee = 25
and
hourly rate = 40
OpenStudy (danjs):
@ganeshie8 wrote the equation out for you above
OpenStudy (anonymous):
whats the t
OpenStudy (danjs):
so you have,
40*t + 25 = 165
What would you do first to solve for the amount of time t ?
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