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f^-1(3) when f(x) = 2x + 3 / 5
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\[f ^{-1}(3) when f(x) \frac{ 2x+3 }{ 5 }\]
@ganeshie8
you want to know for what value of x, the function spits out 3
so set the function equal to 3 and solve x
\[\large 3 = \dfrac{2x+3}{5}\] solve \(x\)
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so x = 6
Yep!
is this right? f(1) when f(x) = 5x + 1 f(x) = 5(1) + 1 x = 6
right!
and last part of the question 3y - 7 = y + 5 -5 - 5 3y - 12 = y y = 6
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Excellent! so all 3 parts have the same answer of 6 is it
Yea it was asking Which of the following statements have the same result? Explain each step in solving each one.
Makes sense!
ok thanks once again! :)
np :)
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