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Mathematics 21 Online
OpenStudy (anonymous):

Suppose h(x) = 3-(x+4 / x-7) and the inverse is (7x-25) / (x-2) Evaluate [h(9)]^-1

OpenStudy (anonymous):

Im confused as to what the brackets mean, as opposed to something like, evaluate h(9^-1)

OpenStudy (ksaimouli):

just plug x=9 for the inverse

OpenStudy (anonymous):

ok, let me try

OpenStudy (ksaimouli):

^-1 means inverse

OpenStudy (anonymous):

I think if I was just to plug in 9 for the inverse it would ask to evaluate h^-1 (9)

OpenStudy (anonymous):

It seems like this wants me to plug in 9 for the original function and then find the inverse?

OpenStudy (ksaimouli):

both ways should give you same answer

OpenStudy (anonymous):

I think they're two different questions

OpenStudy (anonymous):

Cause I've been asked to find both

OpenStudy (ksaimouli):

ohh I see, then for first equation invrse it and plug in

OpenStudy (anonymous):

I got -2, is that right?

OpenStudy (anonymous):

I don't think it is...

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