Question

A collection of quarters and dimes is worth $12.40. There are 67 coins in all.



How many of each coin are there?

Answer 1

like before
\[25x+10(67-x)=1240\]

Answer 2

so wht the answer I can try

Answer 3

Like before, if all are dimes, we have 6.70, so missing 5.70. Need 5.70/(0.25-0.10)=38 quarters.

Answer 4

i think its 48quarters and 4dimes

Answer 5

if it was me i would use one variable
you are going to have to get it to one variable in any case to solve
did you solve \[25x+10(67-x)=1240\]?

Answer 6

so wht they answer

Answer 7

am I right or wrong

Answer 8

PLEASE HELP ANYBODY !!:{

Answer 9

hi

Answer 10

do you still need assistance?

Answer 11

67 = Q +D
AND
$12.70 = (0.25)Q + (0.10)D

Answer 12

if you solve that system of 2 equations, you get

Q = # Quarters = 38
D = # Dimes = 29

Answer 13

thxs a lot your best