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Given f(x) = x + 1 and g(x) = x – 1, find (fg)(x). is it x^2-1
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\(\large\color{black}{ f(x) = x + 1 }\) \(\large\color{black}{ \color{green}{ g(x)} = \color{red}{ x- 1} }\) \(\large\color{black}{ f(\color{green}{ g(x)} ) = (\color{red}{ x- 1} ) + 1 }\) \(\large\color{black}{ f(\color{green}{ g(x)} ) = ? }\)
SolomonZelman I think it might be "f times g"
@jim_thompson5910 is right its f times g
so you'd do (f*g) = f(x)*g(x) = (x+1)*(x-1) = x^2 - 1 which means you are indeed correct
Thank you (:
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