simplify the expression: cubed root of 648
please note that: \[648=8*81=2^{3}*3^{3}\]
The first step is to find the prime factorization of 648. Do you know how to do that?
mathstudent 55 no I do not know how to do that
Then here goes. First, familiarize yourself with a list of the first 10 or 15 prime numbers. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, ...
To find the prime factors of a number start by dividing the number by the smallest prime number it is divisible by. Then keep dividing by that p[rime until it is no longer divisible. Then move on tot he next prime and do the same. In the end, you must end up with 1.
I'll show you an example using the number 630. Let's find the prime factorization of 630.
Set it up like this: |dw:1418574164902:dw|
Now remember the prime numbers. We start with the smallest prime, 2. 630 is divisible by 2, so we divide 630 by 2 to get 315 and write it like this: |dw:1418574240763:dw|
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