Question

(2^x)3x+3x=1

Answer 1

\(\large\color{black}{ (2^x)3x+3x=1 }\) like this, right?

Answer 2

yes

Answer 3

2^x)3x+3x=1=3x(2^x+1)

Answer 4

yes.

Answer 5

is this one that may be useful?

Answer 6

\(\large\color{black}{ 3x(2^x+1)=1 }\) looks certainly better.

Answer 7

How did that happen?

Answer 8

nvm I got it

Answer 9

yes. now we have to divide both sides by 3x, right?

Answer 10

what happens next?

Answer 11

\(\large\color{black}{ 3x(2^x)+3x(1)=1 }\)
\(\large\color{black}{ 3x(2^x+1)=1 }\) like this.

Answer 12

Then it would be like this? (2x+1)=1/3x

Answer 13

do you know what to do next? I'm little confused in it

Answer 14

that does not help your cause, matter of fact it makes it worse

Answer 15

so what's your version of solvong this equation?

Answer 16

eyeball it

Answer 17

huh?

Answer 18

zero works by inspection

Answer 19

what do you mean by eyeball it?

Answer 20

@satellite73

Answer 21

maybe i misunderstood the question

Answer 22

but 0 won't work since 3(0) would be zero too

Answer 23

what if we try to factor this expression
3x*2^x+3x-1=0

Answer 24

if this is the question
\[3x\times2^x+3x-1=0\] then i have no idea how to solve it

Answer 25

http://www.wolframalpha.com/input/?i=3x%282%5Ex%2B1%29-1%3D0
this is the result from wolfram, but it is just the result, not the process.

Answer 26

how about substitution. we will get at one answer and then will write it as (x-a)(....)=1

Answer 27

I can try to find one

Answer 28

So the answer is -1?

Answer 29

it is not -1, that doesn't work.

Answer 30

it doesn't look like answer -1, because 2^(-1)=0.5 and it will not result 1

Answer 31

0.1?

Answer 32

I will get a graph for function f(x)=.....-1 and we will see if 0.1 maybe the zero of function

Answer 33

if you look at the reply of solomon ^ it is there

Answer 34

looks like it might be 0.1

Answer 35

do you have mulptiple choice question?

Answer 36

no, its only a blank question

Answer 37

but nevertheless, it's ok now

Answer 38

ok then. Check by substitution, sorry nobody could get a process in all only answer.