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Mathematics 13 Online
OpenStudy (anonymous):

If x^2+mx+m is a perfect square trinomial, which equation must be true? x^2+mx+m=... (x-1)^2 (x+1)^2 (x+2)^2 (x+4)^2

OpenStudy (solomonzelman):

I am thinking of, that (m/2)^2=m m^2=4m m=\(\large\color{black}{ \pm }\)4

OpenStudy (solomonzelman):

have further questions, please ask...

OpenStudy (anonymous):

No that was my last question. Thanks for helping me so much today.

OpenStudy (solomonzelman):

I just want to verify your answers, although I am pretty much sure that you are smart, even though that the fact that you are a girl is debatable.

OpenStudy (solomonzelman):

answer, not answers. **

OpenStudy (solomonzelman):

which option did you pick?

OpenStudy (anonymous):

complete the square and you want the constant to be 0

OpenStudy (solomonzelman):

it doesn't matter what would the other side be in this case. we are just looking for "m" that would be making a perfect square trinomial (on the left hand side)

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