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If x^2+mx+m is a perfect square trinomial, which equation must be true? x^2+mx+m=... (x-1)^2 (x+1)^2 (x+2)^2 (x+4)^2
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I am thinking of, that (m/2)^2=m m^2=4m m=\(\large\color{black}{ \pm }\)4
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No that was my last question. Thanks for helping me so much today.
I just want to verify your answers, although I am pretty much sure that you are smart, even though that the fact that you are a girl is debatable.
answer, not answers. **
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which option did you pick?
complete the square and you want the constant to be 0
it doesn't matter what would the other side be in this case. we are just looking for "m" that would be making a perfect square trinomial (on the left hand side)
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