Which equation is in standard form & represents a line with slope -1 through the point (-3, 5)? A) -x + y = 5 B) y = -x + 5 C) x + y = 2 D) y = -x + 2
A) y = x + 5 (does not have slope -1, can be eliminated) B) y = -x + 5 (has slope -1) C) y = -x + 2 (has slope -1) D) y = -x + 2 (same eq as eq C) )
Test point (-3, 5) in equations B, C, and D. Also, what does your textbook consider standard form for a linear equation?
you can use the point slope equation again (y-y1) = m(x-x1) (y-5) = -1(x-(-3)) y-5 = -x-3 slope-intercept form y = -x +2 standard form x+y = 2
@tanner23456 Okay, so the answer is C because they ask for standard form. Could you help me with a few more??
yeah, no worries
Do you want me to post them here or on another post?
I don't care. Whatever you want
A sapling, or young tree, is planted in a garden. After 3 years, it is 180 cm tall. After 7 years, it is 368 cm tall. How tall will the tree be after 10 years? A) 587 cm B) 509 cm C) 470 cm D) 548 cm
you could set up and equation something like this y = mx +b x = number of years y = height first we need to find the slope (y2-y1)/(x2-x1) (368-180)/(7-3) 188/4 m = 47 since the tree's height starts at zero the y-intercept is 0 y= 47x now plug in x y=47(10) y=470
Thank you :)
An empty 6-gal water jug weighs 0.5 lb. With 3 c of water inside, the jug weighs 2 lb. Which equation models the jug's weight y when it contains x cups of water? A) y = 0.5x - 0.5 B) y = -0.5x - 0.5 C) y = 0.5x + 0.5 D) y = -0.5x + 0.5
same type of thing. x= cups of water y= weight find the slope (y2-y1)/(x2-x1) (2-0.5)/(3-0) 1.5/3 slope = 0.5 this time the weight starts at 0.5 when x=0 so the y-intercept will be 0.5 y= 0.5x + 0.5
What is the slope for the equation y = 7? A) 0 B) -7 C) Undefined D) 7
If you think about it on the graph y=7 would look something like this. |dw:1418568531142:dw| therefore the slope is 0
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