Question

derivative of (x + 1)^2/secX , wish to compare my steps with yours please

Answer 1

so you can use the quotient rule: \[\frac{ f(x)' }{ g(x) } = \frac{ f'(x)g(x)-f(x)g'(x) }{ g(x)^2 }\]

Answer 2

it would be more simple to transform 1/secx = cosx

Answer 3

it would be something like \[\frac{ \delta (x+1)^2 }{ \delta x \sec(x) } = 2(x+1)\cos(x) + (x+1)^2(-sinx)\]