Question

How do you do this?

Answer 1

\[\frac{ 1 }{ 3 }8^{-\frac{ 2 }{ 3 }}\]

Answer 2

Remember: \(a^{-n} = \dfrac{1}{a^n}\)

Answer 3

I forgot that actually

Answer 4

I assume you mean by "do the problem" to simplify
First, we take care of the negative power
A negative power means a term over the numerator/denominator line:

Answer 5

\(8^{2/3} = (8^{1/3})^2 = (\sqrt[3]{8})^2\)

Answer 6

1/4 times 1/3 is 1/12

Answer 7

yeah

Answer 8

Appreciate it again

Answer 9

welcome