please help me solve the equation 3/2 (x-2)-5=19
and 6=1/5w+7/5w-4
\(\dfrac{3}{2}(x - 2) - 5 = 19\) Is this it?
@agray99
i can't veiw your answer
I didn't give an answer..lol.
Just asking if that's the equation..
the answer to number 1 is x=18 and number 2 is w=25/4 but i need to find the processs
Okay, well first we distribute 3/2 into the parenthesis: \(\dfrac{3}{2}(x - 2)\) To do this we multiply it to both 'x' and '-2'. \(\dfrac{3}{2} \times x = \dfrac{3}{2}x\) \(\dfrac{3}{2} \times -2 = -3\) So we have: \(x - 3 - 5 = 19\) Can you finish that? @agray99
Sorry we have: \(\dfrac{3}{2}x - 3 - 5 = 19\)
Can you finish that? @agray99 Just subtract -3 - 5, add that to both sides, then multiply 2/3 to both sides.
i'm confused as to how we got all that
We distribute 3/2 into the parenthesis..the parenthesis has 'x' and -2' inside of it..distributing 3/2 will be multiplying 3/2 to 'x' and '-2'..and when I did that I came up with 3/2x - 3
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