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Simplify x^2+3-4/x+4
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\[\frac{ x^2+3-4 }{ x+4 }\]
answers \[\frac{ 1 }{ x-4 } where X \neq4 \] \[x-4\] \[x-1 where X \neq1\] \[x-1 where X \neq 4\]
group the constant terms x^2 -1 / x+4 now, since the degree above is bigger than below, you can use long division to obtain the remainder
divide what?
@Directrix
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Is the numerator of the original problem missing an "x" term. Please check. Thanks.
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