A line passes through a point (-2,4), and its y intercept is (0,6). What is the equation of the line that is perpendicular to the first line and passes through the point (5,-4)

Question

anonymous · Answer

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anonymous · Answer

First, find the slope of the first line

m = (6-4)/(0--2) = 2/2 = 1

We want a line that is perpendicular to the first so we will want a slope that is the opposite reciprocal, so the slope of our second line will be (-1).

Now we can use point-slope form to write the equation of the second line containing the point (5, -4) and a slope of (-1)

y - (y1) = m(x - (x1))
y - (-4) = -1(x - (5))
y + 4 = -x + 5
y = -x +1