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Write the point-slope equation of the line through (-2, 1) with a slope of 3. A. y - 1 = 3(x + 2) B. y - 2 = 3(x + 1) C. y + 2 = 3(x - 1)
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@AcademicGurusInc
@LeeEtchison
point slope is \[y-y_1=m(x-x_1)\] m being the slope of the line can you plug in for y1 and x1
i dont know what the x is
you won't need x riight now (x,y) is how the points are placed you will replace x for only \[x_1\] and y for only \[y_1\]
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so -2 - 1?
so a right? @KlOwNlOvE
whats -(-2)?
yes
thank you
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