Question

Write an equation for the line that contains the point (-6, -8) and is parallel to the line 3x – 2y = -12.
A. -3x + 2y = -10
B. -3x + 2y = 2
C. -3x + 2y = 22
D. 2x + 3y = -36

Answer 1

@dan815

Answer 2

@robtobey

Answer 3

i think its b for some reason

Answer 4

Solve 3x – 2y = -12 for y.\[y=\frac{3 x}{2}+6 \]Solve the following for y:\[\frac{y--8}{x--6}=\frac{3}{2} \]

Answer 5

im sorry but there are ????all over what youwrote

Answer 6

b. is the answer.

Answer 7

okthank you so much

Answer 8

can i ask 1 more?

Answer 9

@robtobey

Answer 10

Refer to the attachment

Answer 11

ok well this is a different question

Answer 12

The answer is indeed B. How you do it if you want the explanation is this. Given the equation 3x – 2y = -12. You can simplfy

that equation to -2y=-12-3x

divide that by -2.

y=6+3/2x

3/2 is your slope

point slope formula

y-y1=M(x-x1)

your point is -6,-8

y+8=3/2(x+6)

simplify that to

y+8=3/2x+9

that's the same as y=3/2x+1

all of your answer choices have 2y.

so multiply this by and you get 2y=3x+2

you can shape that to -3x + 2y = 2

plug that in to y

Answer 13

thank you @dtan5457

Answer 14

I answered your latest question, go check it out

Answer 15

i did thanks again