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If p-1 is a factor of (p^4)+(p^2)+p-k. Then what is the value of K? I will give a medal!!
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@perl
lets see
Suppose we have the function f(p) = (p^4)+(p^2)+p-k if p -1 is a factor of (p^4)+(p^2)+p-k then f(1) = 0 so plug in 1
not quite , i wrote f(1) = 0
so 0=(1^4)+(1^2)+1-k
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yes that looks better
so would it be K=3?
Thank you @perl
the intuition here is if i say p-1 is a factor of (p^4)+(p^2)+p-k that means (p^4)+(p^2)+p-k = (p - 1 ) * ( cubic expression in p ) then it makes sense that if p =1 , you will get zero ( 1-1) * ( something) = 0
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