Question

lim X^4 -16X / X^2 + 2X
x -> 0
Help please!

Answer 1

lim x -> 0
\[\frac{ X^4 - 16X }{ X^2 +2X }\]

Answer 2

try to factor each piece as much as possible

Answer 3

you'll find that something cancels

Answer 4

\[X(X^3 - 16)\]
Is this correct?

Answer 5

Like for the top?

Answer 6

correct

Answer 7

\[X(X+2)\]

= \[\frac{ X(X^3 - 16 )}{ X(X-2) }\]

Answer 8

x+2 not x-2

Answer 9

but you have the right idea

Answer 10

yeah sorry wrong button.

Answer 11

what terms cancel?

Answer 12

oh god. I think I figured it out

Answer 13

X's cancel

Answer 14

yes, the ones to the left

Answer 15

Then change the other X's to 0 and solve

Answer 16

yes, then plug in x = 0 and you no longer have to deal with a division by zero error

Answer 17

Thank you so much!

Answer 18

you're welcome