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Binomial distribution http://prntscr.com/5hdija
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It says that 6 appears more than 3 times more than any other number. So if we have P(1) = k P(2)= k P(3)=k P(4)=k P(5)=k P(6) = 3k add those up, probability must equal to 1
and solve for k
Got it. Thanks for the clue
what did you get for k ?
1/8
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yes
so part a) is a binomial distribution problem, with 6 trials. the probability of success , throwing a 1, will be 1/8
i got (a) 0.137 (b) 0.3219 (c) 0.7258
they are all correct
thanks once again (:
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