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Mathematics 18 Online
OpenStudy (junyang96):

Binomial distribution http://prntscr.com/5hdija

OpenStudy (perl):

It says that 6 appears more than 3 times more than any other number. So if we have P(1) = k P(2)= k P(3)=k P(4)=k P(5)=k P(6) = 3k add those up, probability must equal to 1

OpenStudy (perl):

and solve for k

OpenStudy (junyang96):

Got it. Thanks for the clue

OpenStudy (perl):

what did you get for k ?

OpenStudy (junyang96):

1/8

OpenStudy (perl):

yes

OpenStudy (perl):

so part a) is a binomial distribution problem, with 6 trials. the probability of success , throwing a 1, will be 1/8

OpenStudy (junyang96):

i got (a) 0.137 (b) 0.3219 (c) 0.7258

OpenStudy (perl):

they are all correct

OpenStudy (junyang96):

thanks once again (:

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