Ok so I have to solve this equation $$\sqrt{5x-3}=\sqrt{2x+3}$$ Ive got it down to 5x=2x+6 how do i get 2x on the other side I know I divide.

Question

Ok so I have to solve this equation $$\sqrt{5x-3}=\sqrt{2x+3}$$  Ive got it down to 5x=2x+6  how do i get 2x on the other side I know I divide.

anonymous · Answer

@actionsports

campbell_st · Answer

subtract 2x from both sides of the equation... 

so on the left hand side... what is 5x - 2x = ?

anonymous · Answer

attachment

anonymous · Answer

its B a zero exists when 9x - 3=0 or x = 1/3   which means the curve starts at x= 1/3

the comparison graph 3square root x has a zero at the origin

anonymous · Answer

5x-2x is 3x

I just asked my sister and she got me to x=2.4

anonymous · Answer

I put x into the equation and they don't add up

campbell_st · Answer

so then the equation becomes 

3x = 6

solve for x.

anonymous · Answer

3x=6   /:3
x=2

anonymous · Answer

Ok thank you both!