Question

Help please...

Solve the exponential equation.

1/16 = 64^4x-3

Answer 1

\[\frac{ 1 }{ 16 }=64^{4x-3}\]

Answer 2

ok so we better switch to common base

1/16 = 4^(-2)
64^(4x-3) = 4^(3*(4x-3))

can you do it now ?

Answer 3

So pretty much distribute the 3 to the 4x and -3?

Answer 4

but then solve for x

Answer 5

when the base is the same you can equate the the exponents

Answer 6

YES

Answer 7

or if you dont want to do it that way u can take the log of both side

Answer 8

4^(-2) = 4^(3*(4x-3))
4^(-2) = 4^(12x-9)
-2 = 12x-9
7 = 12x
x=7/12