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find the inverse: f(x)=1/2+7^x ... please explain >.<
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y = (1/2) + 7^x
finding the inverse is the same as reflecting the function over the line y=x
yea
sqitch variables x and y, swap them around
x = (1/2) + 7^y
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mhm.. then what??
solve for y x - (1/2) = 7^y
oh wait, its 1/(2+7^x)
\[\log _{7}(x-\frac{ 1 }{ 2 }) = y\]
\[y=1/(2+7^x)\]
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oh
sorry
same process
x = 1 / (2 + 7^y)
wait why wouldn't it be 2x+14yx?
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sorry here
x * (2 +7^y) = 1 2 +7^y = 1/x
7^y = 1/x - 2
\[y = \log _{7}(\frac{ 1 }{ x } -2)\]
THANK YOU SO MUCH
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so y now equals the inverse function \[f ^{-1}(x)\]
no prob
:)
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