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what is the standard form of the equation of the line through (0,-3) with slope 2/5
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All you need to find the equation is a point and a slope, you have both of them. Now just plug it into this formula: \[y-y_1=m(x-x_1)\] And solve for y.
\[(x_1, y_1) = (0, -3)\]
the answer would be -2/5x+y+-3 is that correct
Just make sure it's in the standard form, aka, solved for y. y=mx+b
while m is the slope and b is the free term.
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y-(-3)=2/5(x-0) y+3=2/5x y=2/5x-3
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