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Mathematics 13 Online
OpenStudy (twizttiez):

What is the solution to the system of equations? http://static.k12.com/bank_packages/files/media/mathml_806d916af8f47b8c2a984544c4c1cae0762662bf_1.gif ( ? , ? )

OpenStudy (twizttiez):

@DanJS

OpenStudy (danjs):

hi

OpenStudy (twizttiez):

Hi could you help me on a few questions?

OpenStudy (danjs):

x + y = 5 x - 2y = 2

OpenStudy (twizttiez):

Yeah

OpenStudy (danjs):

solve equation 1 for x =

OpenStudy (twizttiez):

What would i do to do that?

OpenStudy (danjs):

x + y = 5 ---> y = 5 - x see that so far?

OpenStudy (twizttiez):

Yeah

OpenStudy (danjs):

so y = 5-x , put that into equation 2, x - 2y = 2 ----> x - 2(5-x) = 2

OpenStudy (danjs):

x - 10 + 2x = 2

OpenStudy (danjs):

3x = 12 x = 4

OpenStudy (danjs):

use x = 4 in one of the original equations and find out what Y is..

OpenStudy (twizttiez):

Ok

OpenStudy (twizttiez):

so as of now we have (4,?) right?

OpenStudy (danjs):

yes, use that information in one of the first original equations, and find Y

OpenStudy (twizttiez):

And i would have x-2*4=2 right?

OpenStudy (danjs):

close, you put in y=2, we have x so far and need to find the Y

OpenStudy (danjs):

4 - 2*y = 2

OpenStudy (twizttiez):

Ok so is 2 y?

OpenStudy (danjs):

yes

OpenStudy (twizttiez):

Ok so (4,2)?

OpenStudy (twizttiez):

Could you help on a few more?

OpenStudy (danjs):

you can test it out in any of the equations from the question, if x=4 and y=2 does the equation have the same number on both sides?

OpenStudy (twizttiez):

Yes

OpenStudy (danjs):

wait, y=1 not 2

OpenStudy (twizttiez):

Or i think it does

OpenStudy (danjs):

4 - 2*y = 2

OpenStudy (danjs):

2y=2 ---> y =1

OpenStudy (danjs):

(x,y) = (4,1)

OpenStudy (twizttiez):

Okay could you help on 4 more?

OpenStudy (danjs):

yeah , open a new question thread and type @DanJS

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