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is there a point of inflection of function f(x)=-6x+4cosx on the interval [0,2pi], if so can you tell me what it is?
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you are given f(x) what is the first derivative, f ' (x) ?
-6-4sinx f''(x)=-4cos x
correct on both
now set f '' (x) equal to zero and solve for x. What do you get?
pi/2?
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what else
yes pi/2
3pi/2
good
|dw:1418794815619:dw|
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now you need to set up a sign chart to see if f '' changes sign as you pass through these critical points
oh k thank you, yea i know how to find them just got stuck on the inflection thank you for the help
ok great, yw
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