Question

Find the exact value of arccos (sin (pi divided by six)).

Answer 1

\(\bf arccos~(sin~(\dfrac{\pi}{6}))\)

Answer 2

sin(pi/6)=?

Answer 3

use the unit circle ...

Answer 4

30 degrees

Answer 5

or
\[\arccos(\sin(\frac{\pi}{6}))=\arccos(\cos(\frac{\pi}{2}-\frac{\pi}{6}))\]

Answer 6

pi/6 rad =30 deg

Answer 7

we need to know sin(30)

Answer 8

are you might find it easier to use the cofunction of sin

Answer 9

or not are

Answer 10

1/2

Answer 11

arccos(1/2)=?

Answer 12

pi/3

Answer 13

right
now i sorta also like the cofunction idea

Answer 14

\[\arccos(\sin(\frac{\pi}{6}))=\arccos(\cos(\frac{\pi}{2}-\frac{\pi}{6})) \\ =\arccos(\cos(\frac{2\pi}{6})) \\ =\arccos(\cos(\frac{\pi}{3}))=\frac{\pi}{3}\]

Answer 15

if you know about the cofunction thing anyways

Answer 16

but yeah either way pi/3 is your right friend for this one

Answer 17

Thank you! Could you help me with one other?