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5/7x-3=2 solve for x.
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Is it \[\frac{ 5 }{ 7x }-3 = 2 ~~~\text{or}~~~\frac{ 5 }{ 7 }x-3 =2\]
the second one
Alright, so any idea how to start?
I'm assuming you add 3 to both sides, right?
Right!
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So do that now, and then try thinking of what the next step is :)
multiply the reciprocal?
Yeah! \[\frac{ 5 }{ 7 } \times \frac{ 7 }{ 5 }\]
But multiply by 7/5 on both sides :)
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