Question

Which function's graph has a period of 2?
a) y= -4 sin2x
b) y= 3 cosx
c) y= 2 sinpix
d) y= cos(x-pi/2)

Answer 1

a) (2pi)/2 = pi
b) 2pi/1 = 2pi
c) ?

Answer 2

2 sine*pi*x

Answer 3

\(\sin(ax+c)\) then period is given by \(\frac{2\pi}{a}\)

Answer 4

what is the period for c) ?

Answer 5

i dont know

Answer 6

I showed you how.

Answer 7

would it be 2pi/2?

Answer 8

=correct

Answer 9

no

Answer 10

\(\sin(\pi x)=\sin(\pi x+0)\)
\(\sin(ax+b)\)

What number on the first equation corresponds with \(a\) in the second equation?

Answer 11

-4?

Answer 12

\(\sin(\pi x+0)\\\sin(ax+b)\)

what is \(a\) in the second one?

Answer 13

pi

Answer 14

period = \(\frac{2\pi}{a}\)

Answer 15

what is period?

Answer 16

2

Answer 17

correct

Answer 18

so its a?

Answer 19

no

Answer 20

wait its c

Answer 21

correct

Answer 22

yay! thank you

Answer 23

np