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Calculus1
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Find all relative extrema, use the second derivative test where applicable... f(x)=6x-x^2
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well have you found f'?
once we find f' we should find for what x values f'=0 ( i would say f' dne but we don't have to work about that case) then once we find f' we can find derivative of f' to get f''
yeah i already got all of that, f''(x)=-2
So from there where do i go..
and the critical point is x=3
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so f'=6-2x f'=0 when x=3 and f''=-2 f''=-2 means your graph is open down x=3 so what does imply what happens at x=3?
right, its a relative max @ 3
|dw:1418854195547:dw| so what i'm saying is your picture looks sorta like this and yes
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