Someone please help me solve this!!! f^-1(3) when f(x)=2x+3/5
you function is: I can just replace f(x) with a 3.
plug in 3 for f(x) (not f(3), but set f(x)=3 )
Okay, does this mean that it would be 2(3)+3/5??
no, it means that it is 3=2x+3/5
OHHHHHHH okay so now I do what?
soilve for x.
So solve 2x+3 first? then divide it by 5? is that right?
@SolomonZelman
is it y=(2x+3)/5 , it was that?
f(x)=2x+3/5
so 2x is NOT part of the fraction ?
Find the inverse of f(x) then evaluate it at 3.
No
it is easier to plug in 3 instead of y. Isn't it, Isaiah?
F(x)= 2x+3 ---------- 5
Oh, yes, so we are at: 3=(2x+3) / 5 multiply both sides by 5.
what do you get when you multiply both sides by 5, can you tell me?
So would it be.... 5x=2x+3???
@SolomonZelman I only know the traditional method.
If you need the f^(-1)(x) then do the traditional, but for this, I think you see why plugging in 3 for y, is still same as f^(-1)(3).
Okay, am i right with what i said for multiplying by 5?
@nicjohns 3=(2x+3)/5 3* 5 = 5* (2x+3)/5 15=2x+3
Okay and that is my final answer or i solve for x by one step equation?
So subtract 3 from both sides.... 12=2x. Divide by 2 on both sides and equal x=6????
you have to solve for x. isolate the x first by subtracting 3 from both sides, and then by dividing both sides by 2.
I just did that, and put it! x=6!!!!
yes, that is right!
Thank you so much!! I fi open another question so I can give you another medal, can you help me with one more???
I will see if I get more time to help you. yw:)
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