Question

please help
http://oi58.tinypic.com/2mc7syg.jpg

Answer 1

\[\frac{-8((12-6)+3)+4}{(9-2(2+3))}\]Solve for the inner most parenthesis first.

Answer 2

\[\frac{-8(\color{red}{(12-6)}+3)+4}{(9-2\color{red}{(2+3)})}\]

Answer 3

12-6 =6
2+3 = 5

Answer 4

Alright. \[\frac{-8(6+3)+4}{(9-2(5))}\]

Answer 5

Now solve :\[\frac{-8\color{red}{(6+3)}+4}{(9-\color{red}{2(5)})}\]

Answer 6

6+3 = 9
2 x 5 = 10

Answer 7

\[\frac{\color{red}{-8(9)}+4}{\color{red}{(9-10)}}\]

Answer 8

-8 x 9 = -72
9 - 10 = -1

Answer 9

\[\frac{\color{red}{-72+4}}{-1}\]

Answer 10

-72 + 4 = -68

Answer 11

\[\frac{-68}{-1}\]

Answer 12

but it can't be the answer as a fraction...?

Answer 13

What is 68/1

Answer 14

68

Answer 15

There you go.

Answer 16

THANK YOU