MEDAL AND FAN!
Solve for x: 4|2x-2| + 10 =34
A) x=-4, x=2
B) x=4, x=-4
C) x=2, x=-2
D) x=4, x=-2
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OpenStudy (anonymous):
@misty1212 can you help me with this one too?
OpenStudy (anonymous):
@SolomonZelman can you help me?
OpenStudy (misty1212):
\[[2|2x-2|+10=34\]subtract 10 from both sides
OpenStudy (misty1212):
\[4|2x-2|=24\]
OpenStudy (misty1212):
\[8|x-1|=24\] is good too
then divide by \(8\) what do you get?
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OpenStudy (anonymous):
The absolute value of x-1 = 3
OpenStudy (misty1212):
good
then you have to solve
\px-1=3\] and also \[x-1=-3\] both are by adding one to both sides
OpenStudy (misty1212):
\[x-1=3\] and
\[x-1=-3\]
OpenStudy (misty1212):
add one to each side for two answers
OpenStudy (anonymous):
so x=4 and x=-2 =3
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OpenStudy (anonymous):
^_^ Thankies so much @misty1212
OpenStudy (misty1212):
so yes \(x=4\) or \(x=-2\)
OpenStudy (misty1212):
welkies again thanks for the medal
OpenStudy (triciaal):
another approach
first -10 from each side
then divide each side by 4
now you have 2 equations because you have an absolute
on the left , you will take the positive = right hand side and solve
on the left now take the negative = right hand side and solve