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Find cos Θ/2 when 270º<Θ<360º and cosΘ is defined as indicated. cos Θ =√7/4
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\[\cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+\cos(\theta)}{2}}\]
\[\cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+\frac{\sqrt7}{4}}{2}}\]
use the \(-\) not the \(+\) because half an angle in quadrant 4 is in quadrant 2, and in quadrant 2 cosine is negative
is it \[-\sqrt{4-\sqrt{7}}/4+\sqrt{7}\]
@misty1212
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