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write as single trigonometric function: sin(90degrees-theta)/cot(90degrees-theta) PLEASE I KNOW THE ANSWER I JUST NEED SOMEONE TO EXPLAIN IT
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|dw:1418873521702:dw|\[\sin(90-x)=\frac{a}{h}=\cos(x)\]
same with \[\cot(90-x)=\frac{b}{a}=\tan(x)\]
You should know by cofunction identities That sin(90-theta)= cos theta And cot(90-theta)=tan theta http://www.mathwords.com/t/trig_identities.htm So you can rewrite as cos(theta) ---------- tan(theta)
but the her said the answer is just cot theta
teacher
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the teacher is mistaken
unless there is a typo in the question
oh yes my apologies its cos not cot
i understand now
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