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Mathematics 23 Online
OpenStudy (anonymous):

Complete the equation of the graphed linear function in point-slope form. y – 6 = (x – ) The graph of the function goes through point negative 6, 6 and point negative 8, 2.

OpenStudy (anonymous):

OpenStudy (anonymous):

@TheSmartOne

OpenStudy (dan815):

y – 6 = (2-6)/(8-6)(x –6 )

OpenStudy (anonymous):

Im confused :/

OpenStudy (anonymous):

@borak

OpenStudy (anonymous):

you have to fill :- y-y1 = m(x-x1);

OpenStudy (anonymous):

im confused on how to do that

OpenStudy (anonymous):

y1=6 then you go to the see what the x is belong to y1=6

OpenStudy (anonymous):

y1?

OpenStudy (anonymous):

then you find (x1,y1)

OpenStudy (anonymous):

just symbol y1

OpenStudy (anonymous):

im so confused. im so sorry

OpenStudy (anonymous):

o.k lets begin from start

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

you have somthing like that y -6 = (x- )

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the linear function = y -6 = m(x-x1) the point that substitue in this function is (x1,6) and m is the slope

OpenStudy (anonymous):

okay

OpenStudy (ganpat):

Slope for the line is given by m= (y1-y)/(x1-x) where yx1,y1 are the points on the line -6,6 now calculating slope of the line... i.e. m consider any 2 points on the line (refer graph) (-6,6) and (-10,-2) therefore, slope will be m = [-10 - (-6)]/ [-2 - 6] = -4/-8 = 1/2 so you have m = 1/2, (x1,y1) as (-6,6) and the formula m=(y-y1)/(x1-x)

OpenStudy (anonymous):

okay now i am even more confused then i already was O.O

OpenStudy (anonymous):

you can look in the attached picture an tell me what

OpenStudy (anonymous):

the Point is at -6,6?

OpenStudy (anonymous):

depending in the linear function in picture what (x1,6) when y=6

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

when find x1 in the linear function y-6 = m(x- (-6)) =

OpenStudy (anonymous):

then we left to find m or the slope

OpenStudy (anonymous):

(-6,6) is te point

OpenStudy (anonymous):

so i need to find the slope?

OpenStudy (anonymous):

yes and you solve the problem

OpenStudy (anonymous):

let's take 2 points (-8,2) and (-6,6)

OpenStudy (anonymous):

can you find the slope from these 2 points

OpenStudy (anonymous):

would the slope be -6?

OpenStudy (anonymous):

or -1?

OpenStudy (anonymous):

delta {y}/delta{x} (6-2)/(-6 -(-8)) = 4/2 = 2

OpenStudy (anonymous):

delta?

OpenStudy (anonymous):

delta{y} = y1-y2 // y1 y in first point and y2 is the y in second p[oint

OpenStudy (anonymous):

\[\Delta{y}/\Delta{x}\]

OpenStudy (anonymous):

im not quite understanding...

OpenStudy (anonymous):

what the slope mean do you know ?

OpenStudy (anonymous):

it's mean the rate of change in y dpending on change of X

OpenStudy (anonymous):

and calcualte him (slope ) = (y1-y2)/(x1-x2); // the order is imporatnt

OpenStudy (anonymous):

2/4

OpenStudy (anonymous):

?

OpenStudy (anonymous):

4/2 , the y is up and x is down

OpenStudy (anonymous):

(-8,2) (-6,6)

OpenStudy (anonymous):

this is the 2 points (x,y)

OpenStudy (anonymous):

so how would i put that into the equation?

OpenStudy (anonymous):

y-6=4(x-2)?

OpenStudy (anonymous):

we know that the point that choosed is (-6,6)

OpenStudy (anonymous):

so it would be Y-6=4(x-(-6))?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

can you give me the last answer ?

OpenStudy (anonymous):

Was that the last answer?

OpenStudy (anonymous):

sorry ! nothing

OpenStudy (anonymous):

I write in wrong place

OpenStudy (anonymous):

oh...did i get it right though?

OpenStudy (anonymous):

no :D

OpenStudy (anonymous):

ughh

OpenStudy (anonymous):

the slope is 2 not 4

OpenStudy (anonymous):

when we say 6-2/(-8 -(-6)) = 4/2 =2;

OpenStudy (anonymous):

so it would be y-6=2(x-4)

OpenStudy (anonymous):

y- 6 = 2(x+6)

OpenStudy (anonymous):

the point (4,6) not inthe line

OpenStudy (anonymous):

the line dont decripte it (4,6)

OpenStudy (anonymous):

but the equation has a x- i cant change it to x+

OpenStudy (anonymous):

we choose inthe formula the point/points the line descripte them

OpenStudy (anonymous):

formula of the linear with (-)

OpenStudy (anonymous):

the formula of the linear function y-y1 = m(x-x1) // m slope , and (x1,y1) points IN THE LINE

OpenStudy (anonymous):

so it would be y-6=2(x-6)

OpenStudy (anonymous):

(6,6) not point inthe line

OpenStudy (anonymous):

there is minus from the fromula itself

OpenStudy (anonymous):

and the x is negative then the formal will be y-6 = 2(x+6)

OpenStudy (anonymous):

ask any question dont hesitate

OpenStudy (dan815):

y – 6 = (2-6)/(-8-(-6))(x –(-6) )

OpenStudy (anonymous):

it was y-6=2(x-(-6))

OpenStudy (dan815):

did not notice the 'negative' in the question

OpenStudy (anonymous):

yes this right answer

OpenStudy (anonymous):

yeah i found that out after i submitted it....

OpenStudy (anonymous):

i kept getting confused because you put x+6 so i didnt add the negative..

OpenStudy (anonymous):

you know now the answer ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

y= 2x+18

OpenStudy (anonymous):

this same function above after moving sides

OpenStudy (anonymous):

you can check it with any point in the picture

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