Question

please help i am a senior who is failing and doing it on my own!!: what is the equation of the line written in slope-interept form that passes through the point (6,1) and is perpendicular to the line y+2=2(x-3)?

Answer 1

hang on i'll help u! :)

Answer 2

thanks u so much i need so much help!

Answer 3

first lets write the y+2= 2(x-3) into y-intercept form
distribute 2 and subtract two can u do that? :)

Answer 4

These are just the steps to take. But I will let god help you.
My first step: Write the line in y=mx+b form
My second step: Identify m. This is the slope of y=mx+b.
Third step: Realize -1/m is the slope of the perpendicular line.
Fourth step: Perpendicular line to y=mx+b is going to be in the form
y=-1/m * x+c .
Fifth step: Find c by using your point given.
That is replace (x,y) with (6,1) and solve for c.

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Answer 5

That sounded bad

Answer 6

I mean I will let godlovesme help

Answer 7

wow @freckles u r correct!! :)

Answer 8

does that make sense @priea :)