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Mathematics 7 Online
OpenStudy (anonymous):

PLEASE HELP, 2 MORE QUESTIONS TRYING TO GET EXEMPT

OpenStudy (anonymous):

OpenStudy (anonymous):

@wio can you help

OpenStudy (anonymous):

@TheSmartOne @AriPotta can one of you guys help

OpenStudy (anonymous):

@Jesstho.-. @mathmath333 can one of you guys help

OpenStudy (anonymous):

Can you find \(f(2)\) and \(g(2)\) first?

OpenStudy (anonymous):

not sure what you mean

OpenStudy (anonymous):

Well, \[ f(x) = 4x-4 \]Therefore: \[ f(2) = 4(2)-4 = 8-4 = 4 \]

OpenStudy (anonymous):

Basically: \[ (f+3g)(2) = f(2) + 3g(2) \]

OpenStudy (anonymous):

And we know now that \(f(2) =4\), but we still need \(g(2)\).

OpenStudy (anonymous):

okay, i'm following you so far.

OpenStudy (anonymous):

i have this so far : (f + 3(x + 30^2)(2)

OpenStudy (anonymous):

is that right so far?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

We need to find \(g(2)\).

OpenStudy (anonymous):

lol the rest of my work is probably wrong then..

OpenStudy (anonymous):

Remember how I said: \[ (f+3g)(2) = f(2) + 3\,g(2) \]

OpenStudy (anonymous):

okay hold on let me write that down

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

now what?

OpenStudy (anonymous):

find \(g(2)\).

OpenStudy (anonymous):

is it 3?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

I think I wrote something wrong.

OpenStudy (anonymous):

then i don't know, i've always been horrible at math.

OpenStudy (anonymous):

\[ g(2) = ((2)+3)^2 \]

OpenStudy (anonymous):

first add, then square

OpenStudy (anonymous):

25?

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

FINALLY

OpenStudy (anonymous):

So: \[ (f+3g)(2) = f(2) + 3\,g(2) = 4+3(25) \]

OpenStudy (anonymous):

okay, now what? i solve it?

OpenStudy (anonymous):

you just simplify

OpenStudy (anonymous):

which i never understood

OpenStudy (anonymous):

Well \[ 4+3(25) = 4+75 = 79 \]

OpenStudy (anonymous):

thats the answer?

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