Which translation will change figure ABCD to figure A'B'C'D'?
@ms.hi Looking at the pre-image points A, B, C, and D, I viewed the coordinates of those points in contrast with the coordinates of the corresponding image points A', B', C', and D'. A (4,-2) A' (-4,5) B (6,-4) B' (-2, 3) C (2, -5) C' (-6,2) D (2, -3) D" (-6, 4) We are looking for a formula of sorts to indicate the mapping or translation of the points of Quad ABCD to Quad A'B'C'D'
Looking at points A and A' A (4,-2) A' (-4,5) I wrote 4 + k = -4 and solved for k to be -8 The same vale of k, -8, added to each x-coordinate of the remaining 3 points gave the x coordinate of the image point. So far, we know that the translation looks like this (x,y) --> (x - 8, ?)
Looking at the y-coordinates of points A and A' A (4,-2) A' (-4,5) I wrote -2 + c = 5 and solved for c to be +7 The same vale of c, +7, added to each y-coordinate of the remaining 3 points gave the y coordinate of the image point. Therefore, we know that the translation looks like this: (x,y) --> (x - 8, y + 7) The two quadrilaterals are congruent because this mapping preserves size and shape. Do ask if you have questions, okay?
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