What is the equation of the line that passes through the points (-3, 2) and (-5, 8)?
3x - y = -11
3x + y = - 7
3x + y = 5
x + 3y = 3
@iGreen.
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OpenStudy (anonymous):
What do you think it is?
OpenStudy (anonymous):
well you would find the slope so 6/-2
OpenStudy (anonymous):
then divide so x=3
OpenStudy (anonymous):
No, 6 / -2 isn't 3..check again.
OpenStudy (anonymous):
-3
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OpenStudy (anonymous):
Yep, so the slope is -3..
OpenStudy (anonymous):
Which options have slopes of -3?
Convert them into the form of y = mx + b, where m is slope.
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
Like this:
3x - y = -11
Subtract 3x to both sides:
-y = -3x - 11
Multiply -1 to all terms:
y = 3x + 11
So what's the slope of this equation?
OpenStudy (anonymous):
3
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OpenStudy (anonymous):
Yep, so we can eliminate this one, because it has a slope of 3.
OpenStudy (anonymous):
The answer is
B
OpenStudy (anonymous):
y=-3x-7
OpenStudy (anonymous):
Anyway, to find the equation, we can plug in the slope with one of the points into point-slope form.
\(y - y_1 = m(x - x_1)\)
\(y - 2 = -3(x +3)\)
Distribute -3 into the parenthesis:
\(y - 2 = -3x - 9\)
Add 2 to both sides:
\(y = -3x - 7~\Large\color{lime} \checkmark\)