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what are the solutions 1/2x^2+2x+3=0 ?
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multiply everything by 2 to get rid of that fraction
\[x^2 + 4x + 6 = 0\]
(x + )(x + ) = 0
what are the factors of 6?
you need two numbers that when multiplied together give you 6, but when added together give you 4
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And there are no such integers.
or use the quadratic formula
^ I recommend that
wait just solved it i got x = -2+i squareroot2, x = -2- i squareroot 2 is that right?
Looks good.
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yeah i used the quadratic formula :D!
\[x = \frac{ -b +- \sqrt{b^2 - 4*a*c} }{ 2a }\] a=1 b=2 c=6
cool
awesome thanks guys :D
i got something different
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Try simplify your answer
x = -2 + sqrt(2) i x = -2 - sqrt(2) i
Yeah, this is what @Happpily got.
oh, lol i didnt read the "squareroot" thing, beg my pard
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